1993 AMC 8 Problem 22

Attempt Problem 22 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Pat Peano has plenty of 00’s, 11’s, 33’s, 44’s, 55’s, 66’s, 77’s, 88’s and 99’s, but he has only twenty-two 22’s. How far can he number the pages of his scrapbook with these digits?
2222
9999
112112
119119
199199
Answer: D
Concepts:digitssystematic listing
Small hint:
Count how many 22’s appear when numbering pages 11 through 9999
Big hint:
Ten 22’s appear in the units place and ten in the tens place through 99;99; then track the remaining twos past 100100
Solution:
Numbering 11 through 9999 uses ten 22’s in the units place and ten in the tens place, a total of twenty 22’s. Pages 100100 and 101101 use none.
The remaining two 22’s are used on pages 102102 and 112.112. After that, pages 113113 through 119119 need no 2,2, but 120120 would require another 2,2, so he can number up to 119.119.
Thus, the correct answer is D .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.