1993 AMC 8 Problem 1

Attempt Problem 1 of the 1993 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1993 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

1.

Which pair of numbers does not have a product equal to 36?36?
{−4,−9}\{-4, -9\}
{−3,−12}\{-3, -12\}
{12,−72}\left\{\dfrac12, -72\right\}
{1,36}\{1, 36\}
{32,24}\left\{\dfrac32, 24\right\}
Answer: C
Concepts:fraction
Small hint:
Multiply the two numbers in each pair and check which product is not 3636
Big hint:
A negative times a negative is positive, so watch the signs of 12×(−72)\dfrac12 \times (-72)
Solution:
Checking each pair: (−4)(−9)=36,(-4)(-9) = 36, (−3)(−12)=36,(-3)(-12) = 36, 12×(−72)=−36,\dfrac12 \times (-72) = -36, (1)(36)=36,(1)(36) = 36, and 32×24=36.\dfrac32 \times 24 = 36.
Only 12×(−72)=−36\dfrac12 \times (-72) = -36 fails to equal 36.36.
Thus, the correct answer is C .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.