1992 AMC 8 Problem 18

Attempt Problem 18 of the 1992 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

On a trip, a car traveled 8080 miles in an hour and a half, then was stopped in traffic for 3030 minutes, then traveled 100100 miles during the next 22 hours. What was the car’s average speed in miles per hour for the 44-hour trip?
4545
5050
6060
7575
9090
Answer: A
Concepts:distance rate and time
Small hint:
Average speed is total distance divided by total time
Big hint:
Total distance is 80+10080 + 100 miles; total time is 1.5+0.5+2=41.5 + 0.5 + 2 = 4 hours, since the stop still counts
Solution:
The car covered 80+100=18080 + 100 = 180 miles in total, over 1.5+0.5+2=41.5 + 0.5 + 2 = 4 hours (the traffic stop still counts as time).
The average speed is 1804=45\dfrac{180}{4} = 45 miles per hour.
Thus, the correct answer is A .
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