1991 AMC 8 Problem 23

Attempt Problem 23 of the 1991 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1991 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

The Pythagoras High School band has 100100 female and 8080 male members. The Pythagoras High School orchestra has 8080 female and 100100 male members. There are 6060 females who are members in both band and orchestra. Altogether, there are 230230 students who are in either band or orchestra or both. The number of males in the band who are NOT in the orchestra is
1010
2020
3030
5050
7070
Answer: A
Concepts:inclusion-exclusionVenn Diagram
Small hint:
First find how many females are in at least one group, using 100+80−60100 + 80 - 60
Big hint:
Subtract the females from the 230230 total to get the males in at least one group, then use inclusion–exclusion to find how many males are in both groups
Solution:
Females in band or orchestra: 100+80−60=120.100 + 80 - 60 = 120. So males in at least one group: 230−120=110.230 - 120 = 110.
With 8080 males in band and 100100 in orchestra, the males in both are 80+100−110=70.80 + 100 - 110 = 70. Hence males in band but not orchestra: 80−70=10.80 - 70 = 10.
Thus, the correct answer is A .
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