1990 AMC 8 Problem 4

Attempt Problem 4 of the 1990 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

Which of the following could not be the units digit [one’s digit] of the square of a whole number?
11
44
55
66
88
Answer: E
Concepts:units digitperfect square
Small hint:
The units digit of a square depends only on the units digit of the number being squared
Big hint:
Square each of the digits 00 through 99 and record only the units digit of each result
Solution:
The units digit of a square is determined by the units digit of the number squared. Squaring 00 through 99 gives units digits 0,0, 1,1, 4,4, 9,9, 6,6, 5,5, 6,6, 9,9, 4,4, 11.
So a square can only end in 0,0, 1,1, 4,4, 5,5, 6,6, or 99; it can never end in 2,2, 3,3, 7,7, or 88. Among the choices, only 88 is impossible.
Thus, the correct answer is E .
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.