1990 AMC 8 Problem 20

Attempt Problem 20 of the 1990 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1990 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

The annual incomes of 1,0001{,}000 families range from $8200\$8200 to $98,000.\$98{,}000. In error, the largest income was entered on the computer as $980,000.\$980{,}000. The difference between the mean of the incorrect data and the mean of the actual data is
$882\$882
$980\$980
$1078\$1078
$482,000\$482{,}000
$882,000\$882{,}000
Answer: A
Concepts:mean
Small hint:
Only one value changed, so only the total sum changes; the count stays at 10001000
Big hint:
Find how much the one wrong entry inflated the total, then divide that by 10001000
Solution:
Only one entry changed. The incorrect total exceeds the actual total by $980,000−$98,000=$882,000.\$980{,}000 - \$98{,}000 = \$882{,}000.
Since this extra amount is spread over 10001000 families, the means differ by $882,0001000=$882.\dfrac{\$882{,}000}{1000} = \$882.
Thus, the correct answer is A .
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