1989 AMC 8 Problem 6

Attempt Problem 6 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

If the markings on the number line shown are equally spaced, what is the number y?y?
33
1010
1212
1515
1616
Answer: C
Concepts:ratio and proportion
Small hint:
Count how many equal spaces lie between 00 and 2020
Big hint:
There are 55 spaces from 00 to 20,20, so each space is 205=4;\frac{20}{5} = 4; then count the spaces up to yy
Solution:
From 00 to 2020 there are 55 equal spaces, so each space is 205=4.\frac{20}{5} = 4.
The mark labeled yy is 33 spaces from 0,0, so y=3×4=12.y = 3 \times 4 = 12.
Thus, the correct answer is C .
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