1989 AMC 8 Problem 5

Attempt Problem 5 of the 1989 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1989 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

What is the value of

15+9×(6÷3)?-15 + 9 \times (6 \div 3)?

48-48

12-12

3-3

33

1212

Answer: D
Concepts:order of operations

Difficulty rating: 560

Solution:

Inside the parentheses, 6÷3=2.6 \div 3 = 2. Then multiplication comes before addition, so 9×2=18.9 \times 2 = 18.

Finally, 15+18=3.-15 + 18 = 3.

Thus, the correct answer is D .

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