1999 AMC 8 Problem 5

Below is the professionally curated solution for Problem 5 of the 1999 AMC 8, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1999 AMC 8 solutions, or check the answer key.

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Concepts:perimeterarea

Difficulty rating: 770

5.

A rectangular garden 5050 feet long and 1010 feet wide is enclosed by a fence. To make the garden larger, while using the same fence, its shape is changed to a square. By how many square feet does this enlarge the garden?

100100

200200

300300

400400

500500

Solution:

The current length of the fence is 2(50+10)=260=120 2(50 + 10) = 2 \cdot 60 = 120 feet. If all the sides become the same, then each side length is 120÷4=30 120 \div 4 = 30 feet. As such, the area of the square is then 302=900 30^2 = 900 square feet. Note that the original area of the garden is 5010=500 50 \cdot 10 = 500 square feet.

Therefore, the difference is 900500=400 900 - 500 = 400 square feet.

Thus, D is the correct answer.

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