1988 AMC 8 Problem 18

Attempt Problem 18 of the 1988 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

The average weight of 66 boys is 150150 pounds and the average weight of 44 girls is 120120 pounds. The average weight of the 1010 children is
135135 pounds
137137 pounds
138138 pounds
140140 pounds
141141 pounds
Answer: C
Concepts:mean
Small hint:
Find the total weight of the boys and the total weight of the girls separately
Big hint:
Divide the combined total weight by 1010
Solution:
The total weight is 6×1506 \times 150 +4×120+ 4 \times 120 =900+480= 900 + 480 =1380= 1380 pounds.
The average of the 1010 children is 138010=138\dfrac{1380}{10} = 138 pounds.
Thus, the correct answer is C .
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