1986 AMC 8 Problem 18

Attempt Problem 18 of the 1986 AMC 8 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1986 AMC 8 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

18.

A rectangular grazing area is to be fenced off on three sides using part of a 100100 meter rock wall as the fourth side. Fence posts are to be placed every 1212 meters along the fence, including the two posts where the fence meets the rock wall. What is the fewest number of posts required to fence an area 3636 m by 6060 m?
1111
1212
1313
1414
1616
Answer: B
Concepts:perimeteroptimizationfencepost counting
Small hint:
To use the fewest posts, let the 6060 meter side lie along the wall, so the fenced length is as short as possible
Big hint:
The fenced path is 36+60+36=13236 + 60 + 36 = 132 meters; place a post every 1212 meters, counting both ends
Solution:
The fewest posts are used when the wall serves as the longer 6060 meter side, so the fence covers two 3636 meter sides and one 6060 meter side, a path of 36+60+36=13236 + 60 + 36 = 132 meters.
Placing a post every 1212 meters, including both ends, uses 13212+1=12\dfrac{132}{12} + 1 = 12 posts.
Thus, the correct answer is B .
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