2025 AMC 12B Problem 5

Attempt Problem 5 of the 2025 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 12B solutions, or check the answer key.

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5.

Positive integers xx and yy satisfy the equation 57x+22y=400.57x + 22y = 400. What is the least possible value of x+y?x + y?

1010

1111

1313

1414

1515

Answer: E
Concepts:Diophantine Equationmodular arithmetic
Difficulty rating: 1290
Solution:

Modulo 22,22, the equation gives 13x4,13x \equiv 4, so x2(mod22).x \equiv 2 \pmod{22}. With 57x<400,57x \lt 400, the only option is x=2,x = 2, which gives 22y=286,22y = 286, so y=13.y = 13. Then x+y=15.x + y = 15.

Thus, the correct answer is E.

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