2025 AMC 12A Problem 3

Attempt Problem 3 of the 2025 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2025 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A team of students is going to compete against a team of teachers in a trivia contest. The total number of students and teachers is 15.15. Ash, a cousin of one of the students, wants to join the contest. If Ash plays with the students, the average age on that team will increase from 1212 to 14.14. If Ash plays with the teachers, the average age on that team will decrease from 5555 to 52.52. How old is Ash?
2828
2929
3030
3232
3333
Answer: A
Concepts:system of equationsmeanages
Small hint:
Let ss be the number of students; their ages total 12s12s
Big hint:
Adding Ash gives 12s+a=14(s+1)12s + a = 14(s+1) and 55(15−s)+a=52(16−s)55(15-s) + a = 52(16-s)
Solution:
Let ss be the number of students and aa be Ash’s age. The students’ ages total 12s,12s, and adding Ash gives 12s+a=14(s+1)  ⟹  a=2s+14. \begin{aligned} 12s + a &= 14(s+1) \\ &\implies a = 2s + 14. \end{aligned}
There are 15−s15 - s teachers with ages totaling 55(15−s),55(15-s), and adding Ash gives 55(15−s)+a=52(16−s)  ⟹  a=3s+7. \begin{aligned} 55(15-s) + a &= 52(16-s) \\ &\implies a = 3s + 7. \end{aligned}
Setting 2s+14=3s+72s+14 = 3s+7 gives s=7,s = 7, so a=2(7)+14=28.a = 2(7)+14 = 28.
Thus, the correct answer is A.
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