2021 AMC 12A Spring Problem 3

Below is the professionally curated solution for Problem 3 of the 2021 AMC 12A Spring, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Spring solutions, or check the answer key.

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Concepts:place valuelinear equation

Difficulty rating: 1120

3.

The sum of two natural numbers is 17,402.17{,}402. One of the two numbers is divisible by 10.10. If the units digit of that number is erased, the other number is obtained. What is the difference of these two numbers?

10,27210{,}272

11,70011{,}700

13,36213{,}362

14,23814{,}238

15,42615{,}426

Solution:

The larger number ends in 0,0, and erasing that digit divides it by 1010 to give the smaller number. So the larger number is 1010 times the smaller. Writing the smaller number as x,x, the sum is x+10x=11x=17,402,x + 10x = 11x = 17{,}402, giving x=1,582.x = 1{,}582.

The two numbers are 1,5821{,}582 and 15,820,15{,}820, whose difference is 15,8201,582=14,238.15{,}820 - 1{,}582 = 14{,}238.

Thus, the correct answer is D.

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