2023 AMC 12A Problem 4

Attempt Problem 4 of the 2023 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2023 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

How many digits are in the base-ten representation of 85⋅510⋅155?8^5\cdot 5^{10}\cdot 15^5?
1414
1515
1616
1717
1818
Answer: E
Concepts:prime factorizationdigits
Small hint:
Factor each base into primes: 8=23,8=2^3, 15=3⋅515=3\cdot 5
Big hint:
Pair every 22 with a 55 to form a power of 10,10, leaving a small factor
Solution:
Writing everything in primes, 85⋅510⋅155=215⋅510⋅35⋅55=35⋅215⋅515. \begin{gathered} 8^5\cdot 5^{10}\cdot 15^5\\ {}=2^{15}\cdot 5^{10}\cdot 3^5\cdot 5^5\\ {}=3^5\cdot 2^{15}\cdot 5^{15}. \end{gathered}
This equals 35⋅1015=243⋅1015,3^5\cdot 10^{15}=243\cdot 10^{15}, which is 243243 followed by 1515 zeros, for a total of 1818 digits.
Thus, the correct answer is E.
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