2022 AMC 12B Problem 4

Attempt Problem 4 of the 2022 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2022 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

For how many values of the constant kk will the polynomial x2+kx+36x^2 + kx + 36 have two distinct integer roots?
66
88
99
1414
1616
Answer: B
Concepts:Vieta’s Formulasfactorsystematic listing
Small hint:
If the roots are pp and q,q, then pq=36pq = 36 and k=−(p+q)k = -(p+q)
Big hint:
Count the ordered-independent factor pairs of 3636 with two distinct integers, including negatives
Solution:
If the roots are integers pp and q,q, then pq=36pq = 36 and k=−(p+q).k = -(p+q). Distinct roots must have the same sign, so we list factor pairs of 3636 with p≠q.p \ne q.
The positive pairs are (1,36),(2,18),(3,12),(4,9),(1,36), (2,18), (3,12), (4,9), and the negative pairs are (−1,−36),(-1,-36), (−2,−18),(-2,-18), (−3,−12),(-3,-12), (−4,−9).(-4,-9). The pair (6,6)(6,6) is excluded since the roots must be distinct.
Each of these 88 pairs gives a different value of k.k.
Thus, the correct answer is B.
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