2021 AMC 12B Fall Problem 3

Attempt Problem 3 of the 2021 AMC 12B Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

At noon on a certain day, Minneapolis is NN degrees warmer than St. Louis. At 4:004{:}00 the temperature in Minneapolis has fallen by 55 degrees while the temperature in St. Louis has risen by 33 degrees, at which time the temperatures in the two cities differ by 22 degrees. What is the product of all possible values of N?N?
1010
3030
6060
100100
120120
Answer: C
Concepts:absolute valuecasework
Small hint:
At noon the difference is NN; track how each change affects the gap
Big hint:
The new difference is ∣N−5−3∣=2|N - 5 - 3| = 2
Solution:
At noon the gap is N.N. Minneapolis then loses 55 degrees and St. Louis gains 3,3, so the gap changes by 8.8. The new absolute difference is ∣N−8∣=2.|N - 8| = 2.
This gives N=10N = 10 or N=6,N = 6, whose product is 60.60.
Thus, the correct answer is C.
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