2021 AMC 12A Fall Problem 5

Attempt Problem 5 of the 2021 AMC 12A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Fall solutions, or check the answer key.

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5.

Elmer the emu takes 4444 equal strides to walk between consecutive telephone poles on a rural road. Oscar the ostrich can cover the same distance in 1212 equal leaps. The telephone poles are evenly spaced, and the 4141st pole along this road is exactly one mile (52805280 feet) from the first pole. How much longer, in feet, is Oscar's leap than Elmer's stride?

66

88

1010

1111

1515

Answer: B
Concepts:fencepost countingratio and proportion
Difficulty rating: 1270
Solution:

There are 4040 gaps between the first and 4141st poles, so each gap is 528040=132\dfrac{5280}{40} = 132 feet.

Elmer's stride is 13244=3\dfrac{132}{44} = 3 feet and Oscar's leap is 13212=11\dfrac{132}{12} = 11 feet, a difference of 113=811 - 3 = 8 feet.

Thus, the correct answer is B.

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