2021 AMC 12A Fall Problem 3

Attempt Problem 3 of the 2021 AMC 12A Fall below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12A Fall solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Mr. Lopez has a choice of two routes to get to work. Route A is 66 miles long, and his average speed along this route is 3030 miles per hour. Route B is 55 miles long, and his average speed along this route is 4040 miles per hour, except for a 12\tfrac{1}{2}-mile stretch in a school zone where his average speed is 2020 miles per hour. By how many minutes is Route B quicker than Route A?
2342 \tfrac{3}{4}
3343 \tfrac{3}{4}
4124 \tfrac{1}{2}
5125 \tfrac{1}{2}
6346 \tfrac{3}{4}
Answer: B
Concepts:distance rate and timeunit conversion
Small hint:
Route A takes 630\dfrac{6}{30} hour; convert to minutes
Big hint:
Route B splits into 4.54.5 miles at 4040 mph and 0.50.5 mile at 2020 mph
Solution:
Route A takes 630=15\dfrac{6}{30} = \dfrac{1}{5} hour =12= 12 minutes.
Route B has 4.54.5 miles at 4040 mph and 0.50.5 mile at 2020 mph, taking 4.540+0.520\dfrac{4.5}{40} + \dfrac{0.5}{20} =0.1125+0.025= 0.1125 + 0.025 =0.1375= 0.1375 hour =8.25= 8.25 minutes.
The difference is 12−8.25=3.75=33412 - 8.25 = 3.75 = 3\tfrac{3}{4} minutes.
Thus, the correct answer is B.
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