2021 AMC 12B Spring Problem 20

Attempt Problem 20 of the 2021 AMC 12B Spring below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

20.

Let Q(z)Q(z) and R(z)R(z) be the unique polynomials such that z2021+1=(z2+z+1)Q(z)+R(z) \begin{aligned} &z^{2021}+1 \\ &\quad = (z^2+z+1)Q(z)+R(z) \end{aligned} and the degree of RR is less than 2.2. What is R(z)?R(z)?
−z-z
−1-1
20212021
z+1z+1
2z+12z+1
Answer: A
Concepts:polynomialroots of unitymodular arithmetic
Small hint:
Modulo z2+z+1z^2+z+1 we have z3≡1,z^3\equiv 1, since z3−1=(z−1)(z2+z+1)z^3-1=(z-1)(z^2+z+1)
Big hint:
Reduce the exponent 20212021 modulo 3,3, then reduce z2z^2 using z2≡−z−1z^2\equiv -z-1
Solution:
Since z3≡1(modz2+z+1)z^3\equiv 1\pmod{z^2+z+1} and 2021=3⋅673+2,2021=3\cdot 673+2, we have z2021≡z2.z^{2021}\equiv z^2.
So z2021+1≡z2+1.z^{2021}+1\equiv z^2+1. Reducing further with z2≡−z−1,z^2\equiv -z-1, this is −z−1+1=−z.-z-1+1=-z.
Therefore R(z)=−z.R(z)=-z.
Thus, the correct answer is A.
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