2021 AMC 12B Spring Problem 10

Attempt Problem 10 of the 2021 AMC 12B Spring below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2021 AMC 12B Spring solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

10.

Two distinct numbers are selected from the set {1,2,3,4,…,36,37}\{1,2,3,4,\ldots,36,37\} so that the sum of the remaining 3535 numbers is the product of these two numbers. What is the difference of these two numbers?
55
77
88
99
1010
Answer: E
Concepts:Simon’s Favorite Factoring Trickarithmetic sequence
Small hint:
The full set sums to 703;703; if the two chosen numbers are aa and b,b, then 703−a−b=ab703-a-b=ab
Big hint:
Rearrange to (a+1)(b+1)=704(a+1)(b+1)=704 and factor
Solution:
The sum 1+2+⋯+37=703.1+2+\cdots+37=703. If the chosen numbers are aa and b,b, then 703−a−b=ab.703-a-b=ab.
So ab+a+b=703,ab+a+b=703, and adding 11 gives (a+1)(b+1)=704=26⋅11.(a+1)(b+1)=704=2^6\cdot 11.
We need factors a+1,b+1a+1,b+1 between 22 and 38.38. The pair 22⋅32=70422\cdot 32=704 works, giving a=21,a=21, b=31.b=31.
Their difference is 31−21=10.31-21=10.
Thus, the correct answer is E.
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