2020 AMC 12A Problem 4

Attempt Problem 4 of the 2020 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2020 AMC 12A solutions, or check the answer key.

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4.

How many 44-digit positive integers (that is, integers between 10001000 and 9999,9999, inclusive) having only even digits are divisible by 5?5?

8080

100100

125125

200200

500500

Answer: B
Concepts:multiplication principledivisibilitydigits
Difficulty rating: 1200
Solution:

To be divisible by 55 the last digit is 00 or 5,5, and to be even it must be 0.0. So the units digit is fixed.

The leading digit is a nonzero even digit: 2,4,6,82, 4, 6, 8 give 44 choices. Each of the two middle digits is any even digit 0,2,4,6,8,0, 2, 4, 6, 8, giving 55 choices each.

The total is 4551=100.4 \cdot 5 \cdot 5 \cdot 1 = 100.

Thus, B is the correct answer.

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