2019 AMC 12B Problem 7

Attempt Problem 7 of the 2019 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 12B solutions, or check the answer key.

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7.

What is the sum of all real numbers xx for which the median of the numbers 4,6,8,17,4,6,8,17, and xx is equal to the mean of those five numbers?

5-5

00

55

154\dfrac{15}{4}

354\dfrac{35}{4}

Answer: A
Concepts:meanmedian (data)casework
Difficulty rating: 1280
Solution:

The mean is 4+6+8+17+x5=35+x5.\dfrac{4+6+8+17+x}{5}=\dfrac{35+x}{5}.

If x6,x\le6, the median is 6,6, so 35+x5=6\dfrac{35+x}{5}=6 gives x=5,x=-5, which is consistent.

If 6<x<8,6\lt x\lt8, the median is x,x, so 35+x5=x\dfrac{35+x}{5}=x gives x=8.75,x=8.75, not in range. If x8,x\ge8, the median is 8,8, so 35+x5=8\dfrac{35+x}{5}=8 gives x=5,x=5, not in range.

The only solution is x=5,x=-5, so the sum is 5.-5.

Thus, A is the correct answer.

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