2007 AMC 12B Problem 7

Below is the professionally curated solution for Problem 7 of the 2007 AMC 12B, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 12B solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:equilateral trianglesquare (geometry)angle sum

Difficulty rating: 1330

7.

All sides of the convex pentagon ABCDEABCDE are of equal length, and A=B=90.\angle A=\angle B=90^\circ. What is the degree measure of E?\angle E?

9090

108108

120120

144144

150150

Solution:

Because AB=BC=EAAB=BC=EA and A=B=90,\angle A=\angle B=90^\circ, quadrilateral ABCEABCE is a square, so AEC=90\angle AEC=90^\circ and ECEC equals the common side length.

Then CD=DE=EC,CD=DE=EC, so CDE\triangle CDE is equilateral and CED=60.\angle CED=60^\circ. Therefore E=AEC+CED=90+60=150. \angle E=\angle AEC+\angle CED=90^\circ+60^\circ=150^\circ.

Thus, the correct answer is E.

Problem 7 in Other Years