2019 AMC 12B Problem 23

Attempt Problem 23 of the 2019 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2019 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

How many sequences of 00s and 11s of length 1919 are there that begin with a 0,0, end with a 0,0, contain no two consecutive 00s, and contain no three consecutive 11s?
5555
6060
6565
7070
7575
Answer: C
Concepts:partitions and compositionscombinationscasework
Small hint:
Between consecutive 00s there is a block of one or two 11s
Big hint:
With kk zeros there are k−1k-1 blocks of size 11 or 22 whose sizes sum to 19−k19-k
Solution:
No two 00s are adjacent, so the 00s are separated by blocks of 11s, each of size 11 or 22 (never 33). If there are kk zeros, there are k−1k-1 such blocks summing to 19−k19-k ones.
The number of size-22 blocks is (19−k)−(k−1)=20−2k,(19-k)-(k-1)=20-2k, which must satisfy 0≤20−2k≤k−1,0\le20-2k\le k-1, i.e. 7≤k≤10.7\le k\le10.
Summing (k−120−2k)\binom{k-1}{20-2k} over k=7,8,9,10k=7,8,9,10 gives (66)+(74)+(82)+(90)\binom66+\binom74+\binom82+\binom90 =1+35+28+1=1+35+28+1 =65.=65.
Thus, C is the correct answer.
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