1950 AMC 12 Problem 23

Attempt Problem 23 of the 1950 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1950 AMC 12 solutions, or check the answer key.

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23.

A man buys a house for $10,000\$10{,}000 and rents it. He puts 1212%12\dfrac12\% of each month’s rent aside for repairs and upkeep; pays $325\$325 a year taxes and realizes 512%5\dfrac12\% on his investment. The monthly rent is:

$64.82\$64.82

$83.33\$83.33

$72.08\$72.08

$45.83\$45.83

$177.08\$177.08

Answer: B
Concepts:moneypercentagelinear equation
Difficulty rating: 1650
Small Hint:

Let rr be the monthly rent and express the annual rent as 12r12r

Big Hint:

After upkeep and taxes, the annual return must be 5.5%5.5\% of $10,000\$10,000

Solution:

Let the monthly rent be rr dollars. The yearly rent is 12r,12r, of which 10.125=781-0.125=\tfrac78 remains after setting aside the upkeep money. The desired yearly return is 0.055(10,000)=5500.055(10,000)=550 dollars, so 78(12r)325=550. \frac78(12r)-325=550. Hence 10.5r=875,10.5r=875, giving r=83.3,r=83.\overline3, which is $83.33\$83.33 to the nearest cent.

Thus, the correct answer is B.

← Problem 22#22
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