2018 AMC 12B Problem 23

Attempt Problem 23 of the 2018 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

Ajay is standing at point AA near Pontianak, Indonesia, 0∘0^\circ latitude and 110∘110^\circ E longitude. Billy is standing at point BB near Big Baldy Mountain, Idaho, USA, 45∘45^\circ N latitude and 115∘115^\circ W longitude. Assume that Earth is a perfect sphere with center C.C. What is the degree measure of ∠ACB?\angle ACB?
105105
11212112\tfrac{1}{2}
120120
135135
150150
Answer: C
Concepts:3D geometryspherevector
Small hint:
The longitude difference is 360∘−(110∘+115∘)=135∘360^\circ-(110^\circ+115^\circ)=135^\circ
Big hint:
Put both points on a unit sphere and take the dot product of their position vectors
Solution:
The longitudes differ by 360∘−(110∘+115∘)=135∘,360^\circ-(110^\circ+115^\circ)=135^\circ, and BB is at latitude 45∘45^\circ N. Place A=(1,0,0)A=(1,0,0) on the unit sphere.
Then B=(cos⁡45∘cos⁡135∘, cos⁡45∘sin⁡135∘, sin⁡45∘)B=\tiny\left(\cos45^\circ\cos135^\circ,\ \cos45^\circ\sin135^\circ,\ \sin45^\circ\right) =(−12,12,22).=\left(-\tfrac12,\tfrac12,\tfrac{\sqrt2}{2}\right). The dot product is A⋅B=−12,A\cdot B=-\tfrac12, so cos⁡∠ACB=−12\cos\angle ACB=-\tfrac12 and ∠ACB=120∘.\angle ACB=120^\circ.
Thus, the correct answer is C.
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