2018 AMC 12B Problem 23

Attempt Problem 23 of the 2018 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2018 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

23.

Ajay is standing at point AA near Pontianak, Indonesia, 00^\circ latitude and 110110^\circ E longitude. Billy is standing at point BB near Big Baldy Mountain, Idaho, USA, 4545^\circ N latitude and 115115^\circ W longitude. Assume that Earth is a perfect sphere with center C.C. What is the degree measure of ACB?\angle ACB?

105105

11212112\tfrac{1}{2}

120120

135135

150150

Answer: C
Concepts:3D geometryspherevector
Difficulty rating: 2400
Solution:

The longitudes differ by 360(110+115)=135,360^\circ-(110^\circ+115^\circ)=135^\circ, and BB is at latitude 4545^\circ N. Place A=(1,0,0)A=(1,0,0) on the unit sphere.

Then B=(cos45cos135, cos45sin135, sin45)B=\tiny\left(\cos45^\circ\cos135^\circ,\ \cos45^\circ\sin135^\circ,\ \sin45^\circ\right) =(12,12,22).=\left(-\tfrac12,\tfrac12,\tfrac{\sqrt2}{2}\right). The dot product is AB=12,A\cdot B=-\tfrac12, so cosACB=12\cos\angle ACB=-\tfrac12 and ACB=120.\angle ACB=120^\circ.

Thus, the correct answer is C.

← Problem 22#22
Full Exam

Problem 23 in Other Years