2015 AMC 12A Problem 6

Attempt Problem 6 of the 2015 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2015 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6.

Two years ago Pete was three times as old as his cousin Claire. Two years before that, Pete was four times as old as Claire. In how many years will the ratio of their ages be 2:1?2 : 1?
22
44
55
66
88
Answer: B
Concepts:agessystem of equations
Small hint:
Let p,cp,c be their current ages: p−2=3(c−2)p-2=3(c-2) and p−4=4(c−4)p-4=4(c-4)
Big hint:
Solve for pp and c,c, then find nn with p+n=2(c+n)p+n = 2(c+n)
Solution:
Let pp and cc be Pete’s and Claire’s current ages. Then p−2=3(c−2)p-2 = 3(c-2) and p−4=4(c−4).p-4 = 4(c-4).
Solving these gives p=20p = 20 and c=8,c = 8, so Pete is 1212 years older than Claire.
The ratio is 2:12 : 1 when Claire is 12,12, which is 12−8=412 - 8 = 4 years from now.
Thus, the correct answer is B.
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