2014 AMC 12B Problem 7

Attempt Problem 7 of the 2014 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2014 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

For how many positive integers nn is n30−n\dfrac{n}{30-n} also a positive integer?
44
55
66
77
88
Answer: D
Concepts:divisibilityfactoralgebraic manipulation
Small hint:
Rewrite n30−n=3030−n−1\dfrac{n}{30-n} = \dfrac{30}{30-n} - 1
Big hint:
So 30−n30-n must be a positive divisor of 30,30, and the quotient must be at least 22
Solution:
Write n30−n=3030−n−1. \dfrac{n}{30-n} = \dfrac{30}{30-n} - 1.
For this to be a positive integer, 30−n30-n must be a positive divisor of 3030 with 3030−n≥2,\dfrac{30}{30-n} \ge 2, i.e. 30−n≤15.30-n \le 15.
The divisors of 3030 that are at most 1515 are 1,2,3,5,6,10,15,1, 2, 3, 5, 6, 10, 15, giving 77 values of nn (namely 15,20,24,25,27,28,2915, 20, 24, 25, 27, 28, 29).
Thus, the correct answer is D.
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