2013 AMC 12B Problem 7

Attempt Problem 7 of the 2013 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

Jo and Blair take turns counting from 11 to one more than the last number said by the other person. Jo starts by saying “11”, so Blair follows by saying “1,1, 22”. Jo then says “1,1, 2,2, 33”, and so on. What is the 5353rd number said?
22
33
55
66
88
Answer: E
Concepts:triangular number
Small hint:
The turn that ends at nn consists of someone saying 1,2,…,n1, 2, \ldots, n
Big hint:
After the turn ending at n,n, a total of 12n(n+1)\tfrac12 n(n+1) numbers have been said
Solution:
After the turn that counts up to n,n, exactly 1+2+⋯+n=12n(n+1)1 + 2 + \cdots + n = \tfrac12 n(n+1) numbers have been said. For n=9n = 9 that is 45.45. The next turn starts 1,2,…,1, 2, \ldots, so the 5353rd number is the 88th number of that turn, namely 8.8. Thus, the correct answer is E.
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