2013 AMC 12A Problem 3

Attempt Problem 3 of the 2013 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2013 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A flower bouquet contains pink roses, red roses, pink carnations, and red carnations. One third of the pink flowers are roses, three fourths of the red flowers are carnations, and six tenths of the flowers are pink. What percent of the flowers are carnations?
1515
3030
4040
6060
7070
Answer: E
Concepts:fractionpercentage
Small hint:
Six tenths of the flowers are pink and four tenths are red
Big hint:
Two thirds of the pink and three fourths of the red are carnations; add the two amounts
Solution:
Six tenths of the flowers are pink and four tenths are red. Since two thirds of the pink flowers are carnations, pink carnations make up 23⋅610=410\tfrac{2}{3}\cdot\tfrac{6}{10} = \tfrac{4}{10} of the flowers.
Since three fourths of the red flowers are carnations, red carnations make up 34⋅410=310\tfrac{3}{4}\cdot\tfrac{4}{10} = \tfrac{3}{10} of the flowers. Together the carnations are 410+310=710=70%.\tfrac{4}{10} + \tfrac{3}{10} = \tfrac{7}{10} = 70\%.
Thus, the correct answer is E.
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