2012 AMC 12A Problem 3

Attempt Problem 3 of the 2012 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2012 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

A box 22 centimeters high, 33 centimeters wide, and 55 centimeters long can hold 4040 grams of clay. A second box with twice the height, three times the width, and the same length as the first box can hold nn grams of clay. What is n?n?
120120
160160
200200
240240
280280
Answer: D
Concepts:volumeratio and proportion
Small hint:
The capacity is proportional to the volume
Big hint:
The volume is multiplied by 2×3×12 \times 3 \times 1
Solution:
The second box has 2×3×1=62 \times 3 \times 1 = 6 times the volume of the first, so it holds 66 times as much clay.
Therefore n=6⋅40=240.n = 6 \cdot 40 = 240.
Thus, the correct answer is D.
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