2011 AMC 12A Problem 8

Attempt Problem 8 of the 2011 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2011 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

In the eight-term sequence A,A, B,B, C,C, D,D, E,E, F,F, G,G, H,H, the value of CC is 55 and the sum of any three consecutive terms is 30.30. What is A+H?A + H?
1717
1818
2525
2626
4343
Answer: C
Concepts:pattern recognitionalgebraic manipulation
Small hint:
Consecutive triples having equal sums forces the sequence to repeat every three terms
Big hint:
So HH equals B,B, which means A+HA + H is the same as A+BA + B
Solution:
Since A+B+C=B+C+D=30,A + B + C = B + C + D = 30, we get D=A,D = A, and likewise the sequence repeats with period 3.3. Thus H,H, the eighth term, equals B.B.
From A+B+C=30A + B + C = 30 and C=5,C = 5, we have A+H=A+B=30−5=25.A + H = A + B = 30 - 5 = 25.
Thus, the correct answer is C.
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