2009 AMC 12B Problem 22

Attempt Problem 22 of the 2009 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

Parallelogram ABCDABCD has area 1,000,000.1{,}000{,}000. Vertex AA is at (0,0)(0, 0) and all other vertices are in the first quadrant. Vertices BB and DD are lattice points on the lines y=xy = x and y=kxy = kx for some integer k>1,k \gt 1, respectively. How many such parallelograms are there?
4949
720720
784784
20092009
20482048
Answer: C
Concepts:lattice pointstars and barsprime factorization
Small hint:
With B=(b,b)B = (b, b) and D=(d,kd),D = (d, kd), the area of the parallelogram is (k−1)bd(k - 1)bd
Big hint:
You need (k−1)bd=106=26⋅56(k - 1)bd = 10^6 = 2^6 \cdot 5^6; count ordered factorizations into three positive integers
Solution:
Let B=(b,b)B = (b, b) and D=(d,kd)D = (d, kd) with b,d,kb, d, k positive integers and k>1.k \gt 1. The area is (k−1)bd=1,000,000=26⋅56.(k - 1)bd = 1{,}000{,}000 = 2^6 \cdot 5^6.
Each parallelogram corresponds to an ordered triple (k−1,b,d)(k - 1, b, d) of positive integers with product 26⋅56.2^6 \cdot 5^6. The six 22’s distribute among the three factors in (6+22)=28\binom{6 + 2}{2} = 28 ways, and likewise the six 55’s in 2828 ways, giving 282=784.28^2 = 784.
Thus, the correct answer is C.
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