2000 AMC 12 Problem 22

Below is the professionally curated solution for Problem 22 of the 2000 AMC 12, from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2000 AMC 12 solutions, or check the answer key.

All of the real AMC 8, AMC 10, AMC 12, and AIME problems in our complete solution collection are used with official legal permission of the Mathematical Association of America (MAA).

Concepts:polynomialVieta’s Formulascomplex number

Difficulty rating: 2030

22.

The graph below shows a portion of the curve defined by the quartic polynomial P(x)=x4+ax3+bx2+cx+d.P(x) = x^4 + ax^3 + bx^2 + cx + d. Which of the following is the smallest?

P(1)P(-1)

The product of the zeros of PP

The product of the non-real zeros of PP

The sum of the coefficients of PP

The sum of the real zeros of PP

Solution:

The graph crosses the xx-axis exactly twice, both times at positive values, so PP has two real zeros and two non-real (complex conjugate) zeros.

Reading off the graph: the sum of the coefficients is P(1)>3;P(1) \gt 3; P(1)>4;P(-1) \gt 4; the sum of the real zeros is greater than 4.5;4.5; and the product of all zeros is d,d, the yy-intercept, which is less than 6.6.

The product of the real zeros is greater than 4.5,4.5, so the product of the non-real zeros, equal to product of all zerosproduct of real zeros,\dfrac{\text{product of all zeros}}{\text{product of real zeros}}, is less than 64.5<2.\dfrac{6}{4.5} \lt 2.

This is smaller than every other listed quantity.

Thus, the correct answer is C.

Problem 22 in Other Years