2009 AMC 12A Problem 22

Attempt Problem 22 of the 2009 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2009 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

22.

A regular octahedron has side length 1.1. A plane parallel to two of its opposite faces cuts the octahedron into two congruent solids. The polygon formed by the intersection of the plane and the octahedron has area abc,\dfrac{a\sqrt{b}}{c}, where a,a, b,b, and cc are positive integers, aa and cc are relatively prime, and bb is not divisible by the square of any prime. What is a+b+c?a + b + c?
1010
1111
1212
1313
1414
Answer: E
Concepts:3D geometryregular polygonarea
Small hint:
The cutting plane passes through the midpoints of the six edges that do not belong to the two parallel faces
Big hint:
Those midpoints form a regular hexagon with side 12;\dfrac{1}{2}; find its area
Solution:
Let the two parallel faces be triangles. The plane passes through the midpoints of the six edges not on those faces, forming an equilateral hexagon of side 12,\dfrac{1}{2}, which by symmetry is also equiangular and hence regular.
A regular hexagon is six equilateral triangles, so its area is 6⋅34(12)2=338.6\cdot\frac{\sqrt{3}}{4}\left(\frac{1}{2}\right)^2 = \frac{3\sqrt{3}}{8}.
Thus a=3,a = 3, b=3,b = 3, c=8,c = 8, and a+b+c=14.a + b + c = 14.
Thus, the correct answer is E.
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