2008 AMC 12B Problem 5

Attempt Problem 5 of the 2008 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

A class collects $50\$50 to buy flowers for a classmate who is in the hospital. Roses cost $3\$3 each, and carnations cost $2\$2 each. No other flowers are to be used. How many different bouquets could be purchased for exactly $50?\$50?
11
77
99
1616
1717
Answer: C
Concepts:Diophantine Equationparity
Small hint:
If there are rr roses and cc carnations, then 3r+2c=503r + 2c = 50
Big hint:
Since 2c2c and 5050 are even, 3r3r is even, so rr must be even; find how many even rr work
Solution:
Let rr be the number of roses and cc the number of carnations, so 3r+2c=503r + 2c = 50 with r,c≥0.r, c \ge 0.
Because 2c2c and 5050 are even, 3r3r must be even, forcing rr to be even. The largest possible rr is 1616 (since 3⋅17>503 \cdot 17 \gt 50), so r∈{0,2,4,…,16}.r \in \{0, 2, 4, \ldots, 16\}.
That gives 99 values of r,r, each determining a bouquet.
Thus, the correct answer is C.
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