2008 AMC 12A Problem 3

Attempt Problem 3 of the 2008 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2008 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

Suppose that 23\tfrac{2}{3} of 1010 bananas are worth as much as 88 oranges. How many oranges are worth as much as 12\tfrac{1}{2} of 55 bananas?
22
52\dfrac{5}{2}
33
72\dfrac{7}{2}
44
Answer: C
Concepts:ratio and proportion
Small hint:
First find how many oranges a single banana is worth
Big hint:
23\tfrac{2}{3} of 1010 bananas is 203\tfrac{20}{3} bananas, and these equal 88 oranges
Solution:
Since 23\tfrac{2}{3} of 1010 bananas is 203\tfrac{20}{3} bananas, worth 88 oranges, one banana is worth 8÷203=2420=65 8 \div \dfrac{20}{3} = \dfrac{24}{20} = \dfrac{6}{5} oranges.
Then 12\tfrac{1}{2} of 55 bananas is 52\tfrac{5}{2} bananas, worth 52⋅65=3 \dfrac{5}{2} \cdot \dfrac{6}{5} = 3 oranges.
Thus, C is the correct answer.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.