2007 AMC 12B Problem 8

Attempt Problem 8 of the 2007 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2007 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

8.

Tom’s age is TT years, which is also the sum of the ages of his three children. His age NN years ago was twice the sum of their ages then. What is TN?\frac{T}{N}?
22
33
44
55
66
Answer: D
Concepts:ageslinear equation
Small hint:
NN years ago Tom was T−N;T-N; each child was NN years younger
Big hint:
The children then totaled T−3N;T-3N; set T−N=2(T−3N)T-N=2(T-3N)
Solution:
Tom’s age NN years ago was T−N.T-N. His three children were each NN years younger, so their ages then totaled T−3N.T-3N.
The condition gives T−N=2(T−3N), T-N=2(T-3N), so 5N=T5N=T and TN=5.\frac{T}{N}=5.
Thus, the correct answer is D.
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