2006 AMC 12B Problem 14

Attempt Problem 14 of the 2006 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

14.

Elmo makes NN sandwiches for a fundraiser. For each sandwich he uses BB globs of peanut butter at 44¢ per glob and JJ blobs of jam at 55¢ per blob. The cost of the peanut butter and jam to make all the sandwiches is $2.53.\$2.53. Assume that B,B, J,J, and NN are positive integers with N>1.N \gt 1. What is the cost of the jam Elmo uses to make the sandwiches?
$1.05\$1.05
$1.25\$1.25
$1.45\$1.45
$1.65\$1.65
$1.85\$1.85
Answer: D
Concepts:Diophantine Equationprime factorizationcasework
Small hint:
The total cost is N(4B+5J)=253N(4B + 5J) = 253 cents; factor 253253
Big hint:
Test N=11,23,253,N = 11, 23, 253, then determine the numbers of peanut-butter globs BB and jam blobs JJ
Solution:
The total cost in cents is N(4B+5J)=253=11⋅23.N(4B + 5J) = 253 = 11 \cdot 23. Since N>1,N \gt 1, the value of NN is 11,11, 23,23, or 253.253.
If N=253N = 253 then 4B+5J=1,4B + 5J = 1, and if N=23N = 23 then 4B+5J=11;4B + 5J = 11; neither has a positive integer solution.
So N=11N = 11 and 4B+5J=23,4B + 5J = 23, whose only positive solution is B=2,B = 2, J=3.J = 3.
The jam costs N⋅J⋅5N \cdot J \cdot 5¢ =11⋅3⋅5=165= 11 \cdot 3 \cdot 5 = 165 cents, or $1.65.\$1.65.
Thus, the correct answer is D.
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