Question

A circle of radius $2$ is centered at $A.$ An equilateral triangle with side $4$ has a vertex at $A.$ What is the difference between the area of the region that lies inside the circle but outside the triangle and the area of the region that lies inside the triangle but outside the circle?

$8 - \pi$

$\pi + 2$

$2\pi - \dfrac{\sqrt2}{2}$

$4(\pi - \sqrt3)$

$2\pi + \dfrac{\sqrt3}{2}$

Solution:

Let $z$ be the area shared by the circle and triangle. The requested difference is $(\text{circle} - z) - (\text{triangle} - z) = \text{circle} - \text{triangle}.$

The circle has area $\pi \cdot 2^2 = 4\pi,$ and the equilateral triangle has area $\dfrac{\sqrt3}{4}\cdot 4^2 = 4\sqrt3.$ The difference is $4\pi - 4\sqrt3 = 4(\pi - \sqrt3).$

Thus, the correct answer is D.

2015 AMC 12B Problem 14

Solution:

Problem 14 in Other Years