2006 AMC 12A Problem 5

Attempt Problem 5 of the 2006 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Doug and Dave shared a pizza with 88 equally-sized slices. Doug wanted a plain pizza, but Dave wanted anchovies on half of the pizza. The cost of a plain pizza was $8,\$8, and there was an additional cost of $2\$2 for putting anchovies on one half. Dave ate all the slices of anchovy pizza and one plain slice. Doug ate the remainder. Each then paid for what he had eaten. How many more dollars did Dave pay than Doug?
11
22
33
44
55
Answer: D
Concepts:fractionmoney
Small hint:
The plain pizza is $8\$8 for 88 slices, so each plain slice costs $1\$1
Big hint:
Spread the $2\$2 anchovy surcharge over the 44 anchovy slices, then total each person’s cost
Solution:
Each plain slice costs $1.\$1. The $2\$2 anchovy charge is spread over the 44 anchovy slices, adding $0.50\$0.50 each, so an anchovy slice costs $1.50.\$1.50.
Dave ate 44 anchovy slices and 11 plain slice: 4⋅1.5+1=$7.4\cdot 1.5 + 1 = \$7. Doug ate the 33 remaining plain slices: $3.\$3. Dave paid 7−3=$47 - 3 = \$4 more.
Thus, the correct answer is D.
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