2006 AMC 12A Problem 3

Attempt Problem 3 of the 2006 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2006 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

The ratio of Mary’s age to Alice’s age is

3 : 5.

Alice is

30

years old. How old is Mary?

15

18

20

24

50

Mary’s age is

\tfrac{3}{5}

of Alice’s age

Compute

\tfrac{3}{5}\cdot 30

Mary’s age is

\tfrac{3}{5}

of Alice’s, so Mary is

\tfrac{3}{5}\cdot 30 = 18

years old.

Thus, the correct answer is B.

Problem 3 in other years