2005 AMC 12B Problem 4

Attempt Problem 4 of the 2005 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2005 AMC 12B solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

4.

At the beginning of the school year, Lisa’s goal was to earn an A on at least 80%80\% of her 5050 quizzes for the year. She earned an A on 2222 of the first 3030 quizzes. If she is to achieve her goal, on at most how many of the remaining quizzes can she earn a grade lower than an A?
11
22
33
44
55
Answer: B
Concepts:percentage
Small hint:
80%80\% of 5050 quizzes is the number of A’s she needs
Big hint:
She needs 40−2240 - 22 more A’s out of the remaining 2020 quizzes
Solution:
Lisa needs an A on at least 0.8⋅50=400.8 \cdot 50 = 40 quizzes.
She has 2222 already, so she needs 40−22=1840 - 22 = 18 more of the remaining 2020 quizzes.
She can earn a lower grade on at most 20−18=220 - 18 = 2 of them.
Thus, the correct answer is B.
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