2003 AMC 12B Problem 7

Attempt Problem 7 of the 2003 AMC 12B below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12B solutions, or check the answer key.

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7.

Penniless Pete's piggy bank has no pennies in it, but it has 100100 coins, all nickels, dimes, and quarters, whose total value is $8.35.\$8.35. It does not necessarily contain coins of all three types. What is the difference between the largest and smallest number of dimes that could be in the bank?

00

1313

3737

6464

8383

Answer: D
Concepts:system of equationsDiophantine Equationbounding to limit cases
Difficulty rating: 1430
Solution:

Let n,n, d,d, qq be the numbers of nickels, dimes, quarters. Then n+d+q=100n + d + q = 100 and n+2d+5q=167n + 2d + 5q = 167 (dividing the value equation by 55).

Subtracting gives d+4q=67,d + 4q = 67, so d=674q.d = 67 - 4q.

The largest dd is at q=0,q = 0, giving d=67d = 67 (with n=33n = 33). The smallest occurs at q=16,q = 16, giving d=3d = 3 (with n=81n = 81). The difference is 673=64.67 - 3 = 64.

Thus, the correct answer is D.

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