2003 AMC 12A Problem 7

Attempt Problem 7 of the 2003 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2003 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

7.

How many non-congruent triangles with perimeter 77 have integer side lengths?
11
22
33
44
55
Answer: B
Concepts:triangle inequalitypartitions and compositions
Small hint:
The longest side must be less than half the perimeter
Big hint:
The longest side is at most 33
Solution:
Let the sides be a≤b≤ca\le b\le c with a+b+c=7.a+b+c=7. The triangle inequality requires c<a+b,c\lt a+b, so c<3.5,c\lt3.5, forcing c=3.c=3.
Then a+b=4a+b=4 with a≤b≤3,a\le b\le3, giving the triangles 1-3-31\text{-}3\text{-}3 and 2-2-3.2\text{-}2\text{-}3.
Thus, the correct answer is B.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.