2002 AMC 12A Problem 5

Attempt Problem 5 of the 2002 AMC 12A below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 2002 AMC 12A solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

5.

Each of the small circles in the figure has radius one. The innermost circle is tangent to the six circles that surround it, and each of those circles is tangent to the large circle and to its small-circle neighbors. Find the area of the shaded region.
π\pi
1.5π1.5\pi
2π2\pi
3π3\pi
3.5π3.5\pi
Answer: C
Concepts:circle areatangent circles
Small hint:
Each surrounding circle has its center 22 units from the center, so the large circle has radius 33
Big hint:
Subtract the areas of the seven unit circles from the area of the large circle
Solution:
Each of the six outer unit circles is tangent to the central unit circle, so its center is 22 units from the center. Adding one more radius, the large circle has radius 33 and area 9π.9\pi.
The seven unit circles have total area 7π,7\pi, so the shaded region has area 9π−7π=2π.9\pi - 7\pi = 2\pi.
Thus, the correct answer is C.
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