1992 AMC 12 Problem 5

Attempt Problem 5 of the 1992 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

6^6+6^6+6^6+6^6+6^6+6^6=

6^6

6^7

36^6

6^{36}

36^{36}

Factor the repeated summand

6^6

There are exactly six identical terms

Factoring gives

6\cdot6^6=6^{1+6}=6^7.

Thus the correct answer is B.

Problem 5 in other years