1992 AMC 12 Problem 3

Attempt Problem 3 of the 1992 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1992 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

3.

If m>0m\gt0 and the points (m,3)(m,3) and (1,m)(1,m) lie on a line with slope m,m, then m=m=
11
2\sqrt2
3\sqrt3
22
5\sqrt5
Answer: C
Concepts:slope formulaquadratic equation
Small hint:
Write the slope between the two given points
Big hint:
Set m−31−m=m\frac{m-3}{1-m}=m and use the positivity condition
Solution:
The slope condition gives m−31−m=m. \frac{m-3}{1-m}=m. Therefore m−3=m−m2,m-3=m-m^2, so m2=3.m^2=3. Since m>0,m\gt0, we obtain m=3.m=\sqrt3.
Thus the correct answer is C.
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