1988 AMC 12 Problem 15

Attempt Problem 15 of the 1988 AMC 12 below, then check your answer against the professionally curated solution from LIVE by Po-Shen Loh. You can also try the full timed exam, view all 1988 AMC 12 solutions, or check the answer key.

All problems are used with official legal permission of the Mathematical Association of America (MAA).

15.

If aa and bb are integers such that x2−x−1x^2-x-1 is a factor of ax3+bx2+1,ax^3+bx^2+1, then bb is
−2-2
−1-1
00
11
22
Answer: A
Concepts:polynomial divisibilitymodular reductioncoefficient comparison
Small hint:
Reduce powers using x2≡x+1x^2\equiv x+1
Big hint:
A polynomial of degree below 22 divisible by the quadratic must be zero
Solution:
Modulo x2−x−1,x^2-x-1, we have x2≡x+1x^2\equiv x+1 and x3≡2x+1.x^3\equiv2x+1. Thus the polynomial is congruent to (2a+b)x+(a+b+1).(2a+b)x+(a+b+1). Both coefficients must vanish, so 2a+b=02a+b=0 and a+b=−1.a+b=-1. Hence a=1a=1 and b=−2.b=-2.
Thus the correct answer is A.
LIVE by Po-Shen Loh
Programs

LIVE Classes

Self-Paced Classes

Stars

Scholarship

About Us

Who Is Po-Shen Loh?

Email Contact

Newsletter

Jobs

Become a Star

For a more Thought Full world.

© 2026 Expii, Inc.